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How to choose a wire cross section for 12 volt lighting networks

 

How to choose a wire cross section for 12 volt lighting networksIn conversations with customers when discussing 12-volt halogen lighting, for some reason the word "low current" often flickers, which characterizes the corresponding attitude to the choice of wires - which is at hand, then we use it, the voltage is safe.

The voltage of 12 volts is really safe, in the sense that touching a bare wire with such voltage is simply not felt, but the currents in such circuits flow quite large (see. highlights of using safe voltage in everyday life).

Consider food as an example ordinary halogen lamp with a power of 50 W, the current in the primary circuit of the transformer I = 50W / 220V = 0.23A (or, more precisely, a little more, taking into account the efficiency of the transformer), while the current I = 50W / 12V = 4.2 A flows in the secondary circuit of 12 V, which is already 18 times more. If you do not take this fact into account, you may encounter very unpleasant surprises.

One day a man came to me for a consultation and told what he had done in his house halogen lighting, used a reliable induction transformer 1000W at a load of 900W, spent from mounting box a separate wire to each lamp, but at the moment of switching on the wires simply caught fire, and those wires that led from the transformer output to the mounting box.

To the question about the section of the laid wires - the answer: "An ordinary section, as everywhere else - 1.5 mm2". In stationary mode, I = 900W / 12V = 75A should flow through this wire, and even more when switched on. The cross-section of the copper wire under such conditions should be at least 16 mm2. Hence the conclusion: It is important not to forget about the increased currents in the 12 volt circuits and, accordingly, choose the wires. This, however, is sometimes completely insufficient.

Very often we have to deal with complaints that when using transformers of high power (in this case, 200W is already high power), supplying several lamps, the brightness of the lamps decreases markedly with increasing distance from the transformer. Attempts to deal with this problem by increasing the power of the transformer, of course, do not lead to an improvement in the situation, especially since the increase in the power of the lamps used does not help. The fact is that the cause of this phenomenon is commonplace voltage drop on wires in accordance with Ohm's law.

We illustrate what was said on a concrete example:

Suppose you need to power a group of three lamps of 50W each, located at a distance L from the transformer, as shown in the figure:

12V Lighting Network Diagram

The equivalent circuit has the form:

Equivalent circuit of 12 V lighting network

Resistance of each lamp Rl = U2/ P = 2.88 Ohm, and the resistance of the wire with a length L and a cross section S

Where ρ - resistivity, in this case copper (0.0173 Ohm mm2/ M).

If voltage U is supported at the transformer output0 = 12 V, then the current through each lamp

and the power released in the lamp

Using these formulas, easy to calculate power versus wire length. The calculation results are shown in the table (if you click on the picture, the table will load in a larger format):

power dependence on wire length

As can be seen from the table, power drops pretty quickly with increasing wire lengths, This is even more clearly seen in the graphs:

Loss of lamp power depending on the length of the supply wires

Fig. 3. Loss of lamp power depending on the length of the supply wires


It is possible to avoid noticeable unevenness in the luminous flux of lamps not only through the use of a large cross-section wire, but also by dividing the lamps into groups fed by individual wires, in the limit feeding each lamp with its own wire. In any case, when purchasing lighting equipment, it is useful to ask the seller to give accurate recommendations on the choice of wire cross-section and installation diagram.

Specific recommendations for choosing the wire cross section in the 12 V lighting circuit when using electronic and induction transformers can be found in the corresponding tables.


Tables for selecting the cross-section of wires in low-voltage lighting circuits

As shown earlier, from the analysis of power losses in 12 V lighting networks, the cross-section of wires for halogen lighting of 12 volts should be selected taking into account the total power of the lamps connected to the transformer and the length of these wires.

The approach to determining the cross section of the wires depends on which source is used to power the circuit: electronic or induction. The permissible length of wires in the secondary circuit of electronic power supplies, as a rule, cannot exceed 2 meters (in very rare cases, lengths of up to 3 meters are allowed for high-power transformers). In this case use a wire with the cross section specified in the transformer documentation. If such data are not available, you can tentatively use the data from the table:

Cross-sectional table of copper wires in a 12 V lighting circuit up to 2 meters long (for electronic power supplies). If you click on the picture, the table will load in a larger format.

Cross-sectional table of copper wires in a 12 V lighting circuit up to 2 meters long

When using induction transformers, the length of the wire in the secondary circuit is limited only by the voltage drop across the wires and, therefore, can be significantly larger than electronic (pulse) power supplies, subject to compensation by increasing the cross section of the wire.

Below is given table for choosing the cross-section of wires depending on the total power of the lamps connected to the secondary winding of the induction transformer and the length of these wires. It should be borne in mind that the lamps can be divided into groups, each connected with its own wire, in this case, the cross section of the group wire is determined by the table for each group separately. In the limit, it is possible to connect each lamp with its own wire.

Cross-sectional table of copper wires in the 12 V lighting circuit (for induction transformers).

Cross-sectional table of copper wires in a 12 V lighting circuit up to 2 meters long (for electronic power supplies)

See also at bgv.electricianexp.com:

  • Home-made step-down transformer for damp rooms
  • The specifics of the installation of lighting lines with electronic transformers
  • Electronic Transformers: Purpose and Typical Use
  • How to choose a cable section - designer tips
  • How to calculate cable for extension cable

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    Comments:

    # 1 wrote: | [quote]

     
     

    An interesting article ... The truth is ambivalent. I am from that category of people who were not very serious (before reading this article) to 12V networks, considering it a weak point ...

    In principle, everything is convincingly written! We need to reconsider our attitude to such chains ...

    And what about LED strip? There recommendations for their connection clearly go against this article ...

     
    Comments:

    # 2 wrote: | [quote]

     
     

    Said fairly accessible and correct. For greater understanding, for those who have never contacted this, imagine the circuit extending from the transformer as a vertical distribution of the water supply when supplying water from below. Many have come across this and remember that in the evening, when everyone returns from work at about the same time, they turn on the water at the same time, then the water pressure is enough only to the middle of this high-rise, and the higher the pressure is weaker and weaker. Two conclusions follow from this: 1) all the wires for one group of lamps powered from one transformer must be of the same length, otherwise you will be tormented by the question of how to eliminate the difference in brightness of the glow of the lamps in the group (see above about the water pressure); 2) to fulfill the first condition, it is enough to arrange the transformer and lamps in the shape of a sun-transformer in the middle, and at the ends of the rays your lamps. To distribute the currents from a powerful transformer, it is better to use two pads used for working zero or for grounding, a sufficient section, and already connect wires for connecting lamps from them.You can use intermediate blocks of a smaller cross section to power several groups with a large spread in the area of ​​your lamps, but observing the length of the wires from the transformer to each lamp as branches on a tree. Good luck!

     
    Comments:

    # 3 wrote: | [quote]

     
     

    If you can send recommendations for working with LED strip, I would like to know the opinion of a specialist of a higher profile.

     
    Comments:

    # 4 wrote: | [quote]

     
     

    The main problem is, first of all, to consider 12V networks as LOW-VOLTAGE, because in reality low-current networks are local area networks, and wired broadcasting networks (remember radio points in your grandmother’s kitchen?) - and for calling 12V networks low-current "I always make a comment -" not a low-voltage network, but a low-voltage network! "

     
    Comments:

    # 5 wrote: | [quote]

     
     

    Very entertaining article, many thanks to its author.

     
    Comments:

    # 6 wrote: Yuri | [quote]

     
     

    Quote: Vyacheslav
    And what about LED strip? There recommendations for their connection clearly go against this article ...

    No cut with the article.
    In a tape printed conductors. The length of the tape is 5 m and they cannot be connected in series more than this length. That is, it is impossible to connect several tapes of full length one after another, you must pull your conductors to the next tape. But at the same time, all tapes with their conductors can be connected to one power source. Such a circuit can be called radial-trunk, where the tapes are connected radially to the IP, and the LEDs in the LED are trunk, i.e. one by one.
    According to the rules, low-voltage networks are networks of signaling, automation, etc., they can be 24, 36, or even 220 V, so you do not need to bind the circuit current and voltage. Here, our batteries consist of 30 separate elements (cans), i.e. these cans are completely independent, each with its own case and you can dial a battery from an arbitrary number of cans. The voltage of the element is 2 V (actually 2.2 V, like any acid element), the capacity is 2500 A * hour. So, the current of the standard 10 hour mode of such a jar is 250 A (it will work for 10 hours at such a current). Accordingly, you can discharge and high currents. She has a short-circuit current of 16,000 A (16 kiloamperes!). Who will say that the current is small? And the voltage is only 2 V, safe even when you touch the tongue.

     
    Comments:

    # 7 wrote: | [quote]

     
     

    When calculating for LED lamps (3 pcs) MR16, 12 volts, 5 watts, the resistance of the lamps is 28.8 Ohms (according to the formula). The current through each lamp is from 0.417A for 0 m and 0.398 for 20 m. With a cable length of 10 meters (1.5), the resistance is 0.11, the current per lamp: 3 pieces - 0.407, 10 pieces - 0.388, 20 - 0.359, respectively 0 m - 5 watts, 20 m - 4.55 watts. The drop is not very significant, but with a sharp increase in the number of lamps (100 pcs), the power allocated to the lamp drops sharply. Conclusion: up to 10 lamps with a cable up to 5 m will fall, but visually you will not see it, or the shorter the cable, the more lamps you can connect, and vice versa.

     
    Comments:

    # 8 wrote: | [quote]

     
     

    Thank you so much. I make wiring for two floodlights on the boat. 12V They are modern, LED, but when I measured the consumption current, it turned out 4.5 / A per one. almost 50W, nifiga yourself LEDs, like a halogen in the headlight of a car. I thought about the cross-section of wires 2.5 mm.kv. and installing the reels. The article convinced of the correctness of suspicions.))
    Thanks again.

     
    Comments:

    # 9 wrote: | [quote]

     
     

    VLaDISLAV

    If you can send recommendations for working with LED strip, I would like to know the opinion of a specialist of a higher profile.

    Ohm's law to help you. :)

    For normal power supplies, indicate the maximum allowable wire length or the length of the LED strip. In addition, the article indicates everything necessary for the calculations.

     
    Comments:

    # 10 wrote: Vasya | [quote]

     
     

    And you are aware that when the lamp lights up, the resistance becomes 10 times greater than the cold one, for some reason it’s not your account.

     
    Comments:

    # 11 wrote: Vladimir | [quote]

     
     

    The LED strip with 5050 LED housings has a power of 14.4 W / m. On the drum 5 meters - 72 watts.We get the current strength in 72/12 = 6 A.

    Based on the tables, the cross-section of the wires should be about 0.9 mm2. However, on the tape itself, factory wires of a very small cross section are displayed. And they work, they don’t melt. How so?

     
    Comments:

    # 12 wrote: | [quote]

     
     

    Everything said in the article applies exclusively to halogen lamps (which have long gone out of fashion)! And in no way connected with LED lighting!

    If we take a copper wire with a cross section of 1.5 mm2, then the resistivity of 100 (!) Meters will be only 1.15 Ohm. This is an absolutely insignificant figure for LEDs, since each LED strip has resistors of several hundred (!) Ohms.

    For example, if the resistors in the tape are 180 Ohms, then at these 100 meters less than one (!) Percent of power will be lost, and this with a cross-section of only 1.5 mm2.

    So read carefully and switch to 12-volt LED lighting!

     
    Comments:

    # 13 wrote: Sergei | [quote]

     
     

    Thanks for the advice.